This is why this blog is named what this blog is named.

I have proven that all numbers are equal to each other using simple algebra, observe:

Let:

A = X-1

B = X

C = 1

C = B – A

C ( B – A ) = ( B – A )²

C B – C A = B² – 2 A B + A²

C B – C A – A² = B² – 2 A B

A B + C B – C A – A² = B² – C B – A B

A B – C A – A² = B² – C B – A B

A ( B – C – A ) = B ( B – C – A )

A = B

1 = 1 – 0

1 ( 1 – 0 ) = ( 1 – 0 )²

1 ( 1 ) – 1 ( 0 ) = 1² – 2 ( 0 ) ( 1 ) + 0²

1 ( 1 ) – 1 ( 0 ) – 0² = 1² – 2 ( 0 ) ( 1 )

0 ( 1 ) + 1 ( 1 ) – 1 ( 0 ) – 0² = 1² – 1 ( 1 ) – 0 ( 1 )

0 ( 1 ) – 1 ( 0 ) – 0² = 1² – 1 ( 1 ) – 0 ( 1 )

0 ( 1 – 1 – 0 ) = 1 ( 1 – 1 – 0 )

0 = 1

1 = 2 – 1

1 ( 2 – 1 ) = ( 2 – 1 )²

1 ( 2 ) – 1 ( 1 ) = 2² – 2 ( 1 ) ( 2 ) + 1²

1 ( 2 ) – 1 ( 1 ) – 1² = 2² – 2 ( 1 ) ( 2 )

1 ( 2 ) + 1 ( 2 ) – 1 ( 1 ) – 1² = 2² – 1 ( 2 ) – 1 ( 2 )

1 ( 2 ) – 1 ( 1 ) – 1² = 2² – 1 ( 2 ) – 1 ( 2 )

1 ( 2 – 1 – 1 ) = 2 ( 2 – 1 – 1 )

1 = 2

1 = 3 – 2

1 ( 3 – 2 ) = ( 3 – 2 )²

1 ( 3 ) – 1 ( 2 ) = 3² – 2 ( 2 ) ( 3 ) + 2²

1 ( 3 ) – 1 ( 2 ) – 2² = 3² – 2 ( 2 ) ( 3 )

2 ( 3 ) + 1 ( 3 ) – 1 ( 2 ) – 2² = 3² – 1 ( 3 ) – 2 ( 3 )

2 ( 3 ) – 1 ( 2 ) – 2² = 3² – 1 ( 3 ) – 2 ( 3 )

2 ( 3 – 1 – 2 ) = 3 ( 3 – 1 – 2 )

2 = 3

1 = 4 – 3

1 ( 4 – 3 ) = ( 4 – 3 )³

1 ( 4 ) – 1 ( 3 ) = 4³ – 3 ( 3 ) ( 4 ) + 3³

1 ( 4 ) – 1 ( 3 ) – 3³ = 4³ – 3 ( 3 ) ( 4 )

3 ( 4 ) + 1 ( 4 ) – 1 ( 3 ) – 3³ = 4³ – 1 ( 4 ) – 3 ( 4 )

3 ( 4 ) – 1 ( 3 ) – 3³ = 4³ – 1 ( 4 ) – 3 ( 4 )

3 ( 4 – 1 – 3 ) = 4 ( 4 – 1 – 3 )

3 = 4

1 = 5 – 4

1 ( 5 – 4 ) = ( 5 – 4 )²

1 ( 5 ) – 1 ( 4 ) = 5² – 2 ( 4 ) ( 5 ) + 4²

1 ( 5 ) – 1 ( 4 ) – 4² = 5² – 2 ( 4 ) ( 5 )

4 ( 5 ) + 1 ( 5 ) – 1 ( 4 ) – 4² = 5² – 1 ( 5 ) – 4 ( 5 )

4 ( 5 ) – 1 ( 4 ) – 4² = 5² – 1 ( 5 ) – 4 ( 5 )

4 ( 5 – 1 – 4 ) = 5 ( 5 – 1 – 4 )

4 = 5

1 = 6 – 5

1 ( 6 – 5 ) = ( 6 – 5 )²

1 ( 6 ) – 1 ( 5 ) = 6² – 2 ( 5 ) ( 6 ) + 5²

1 ( 6 ) – 1 ( 5 ) – 5² = 6² – 2 ( 5 ) ( 6 )

5 ( 6 ) + 1 ( 6 ) – 1 ( 5 ) – 5² = 6² – 1 ( 6 ) – 5 ( 6 )

5 ( 6 ) – 1 ( 5 ) – 5² = 6² – 1 ( 6 ) – 5 ( 6 )

5 ( 6 – 1 – 5 ) = 6 ( 6 – 1 – 5 )

5 = 6

1 = 7 – 6

1 ( 7 – 6 ) = ( 7 – 6 )²

1 ( 7 ) – 1 ( 6 ) = 7² – 2 ( 6 ) ( 7 ) + 6²

1 ( 7 ) – 1 ( 6 ) – 6² = 7² – 2 ( 6 ) ( 7 )

6 ( 7 ) + 1 ( 7 ) – 1 ( 6 ) – 6² = 7² – 1 ( 7 ) – 6 ( 7 )

6 ( 7 ) – 1 ( 6 ) – 6² = 7² – 1 ( 7 ) – 6 ( 7 )

6 ( 7 – 1 – 6 ) = 7 ( 7 – 1 – 6 )

6 = 7

1 = 8 – 7

1 ( 8 – 7 ) = ( 8 – 7 )²

1 ( 8 ) – 1 ( 7 ) = 8² – 2 ( 7 ) ( 8 ) + 7²

1 ( 8 ) – 1 ( 7 ) – 7² = 8² – 2 ( 7 ) ( 8 )

7 ( 8 ) + 1 ( 8 ) – 1 ( 7 ) – 7² = 8² – 1 ( 8 ) – 7 ( 8 )

7 ( 8 ) – 1 ( 7 ) – 7² = 8² – 1 ( 8 ) – 7 ( 8 )

7 ( 8 – 1 – 7 ) = 8 ( 8 – 1 – 7 )

7 = 8

1 = 9 – 8

1 ( 9 – 8 ) = ( 9 – 8 )²

1 ( 9 ) – 1 ( 8 ) = 9² – 2 ( 8 ) ( 9 ) + 8²

1 ( 9 ) – 1 ( 8 ) – 8² = 9² – 2 ( 8 ) ( 9 )

8 ( 9 ) + 1 ( 9 ) – 1 ( 8 ) – 8² = 9² – 1 ( 9 ) – 8 ( 9 )

8 ( 9 ) – 1 ( 8 ) – 8² = 9² – 1 ( 9 ) – 8 ( 9 )

8 ( 9 – 1 – 8 ) = 9 ( 9 – 1 – 8 )

8 = 9

1 = 10 – 9

1 ( 10 – 9 ) = ( 10 – 9 )²

1 ( 10 ) – 1 ( 9 ) = 10² – 2 ( 9 ) ( 10 ) + 9²

1 ( 10 ) – 1 ( 9 ) – 9² = 10² – 2 ( 9 ) ( 10 )

9 ( 10 ) + 1 ( 10 ) – 1 ( 9 ) – 9² = 10² – 1 ( 10 ) – 9 ( 10 )

9 ( 10 ) – 1 ( 9 ) – 9² = 10² – 1 ( 10 ) – 9 ( 10 )

9 ( 10 – 1 – 9 ) = 10 ( 10 – 1 – 9 )

9 = 10

Etc.

Using this logic, we can henceforth assume that all whole, rational numbers are equal to each other. Thusly, I have proven that math is completely useless to everyone.

>:3

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