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Tuesday, March 22, 2011

I need a new PC

Don't get me wrong, I love my MacBook Pro, but it doesn't have the guts to do very intense rendering. It also can't run most of the programs i love, like skifree and AutoCAD. Ugh, too damn expensive. I'm broke and my parents won't help me (I'm 16). So, if someone would please donate to my paypal account it would be much appreciated.

YES I KNOW IT'S PATHETIC.

Monday, February 21, 2011

If the auto industry had taken the computer industry as its model, we would all be driving cars with the following characteristics:

1. For no reason whatsoever your car would crash twice a day.

2. If you tried to execute a maneuver your car didn’t like, it would shut down and refuse to restart until you reinstalled the engine.

3. Only one person at a time could use the car unless you bought “CarNT”

4. Macintosh would make a car that was powered by the sun, was reliable, five times as fast, and twice as easy to drive—but it would only run on 5% of the roads.

5. The airbag system would ask, “Are you sure?” before deploying.

6. Occasionally, for no apparent reason, your car would lock you out and refuse to let you in until you simultaneously lifted the door handle, turned the key and grabbed hold of the antenna.

7. GM would require all car buyers to purchase a deluxe set of Rand McNally road maps (now a GM subsidiary), even though drivers never needed nor wanted them. Any attempt on the driver’s part to delete this option would immediately cause the car’s performance to diminish by 50% or more. Moreover, GM would become a target for investigation by the Justice Department.

8. Every time GM introduced a new model, car buyers would have to learn to drive all over again because none of the controls would operate in the same manner as the old car.

9. You’d have to press the “start” button to turn off the engine.

Wednesday, February 16, 2011

More Rendering Math Useless...

.99 repeated is equal to 1

x = .99 repeated

10x = 9.99 repeated

9x = 9

x = 1

.99 repeated = 1

YES I KNOW IT'S NON-LINEAR, I JUST PUT IN THE EQUIVALENT VALUES

Tuesday, February 8, 2011

This pisses me off...

With these grades, i'll never get into the University of Minnesota's Honors Program!

Environmental Science: A-
English 10 Honors: A
Winter Recreational Sports I: A
PreCalculus Honors: B+
AutoCAD I: A
Global Studies: A
German II: A

If i can't get these up, i'm screwed...

Wednesday, February 2, 2011

This is why this blog is named what this blog is named.

I have proven that all numbers are equal to each other using simple algebra, observe:

Let:

A = X-1

B = X

C = 1

C = B – A

C ( B – A ) = ( B – A )2

C B – C A = B2 – 2 A B + A2

C B – C A – A2 = B2 – 2 A B

A B + C B – C A – A2 = B2 – C B – A B

A B – C A – A2 = B2 – C B – A B

A ( B – C – A ) = B ( B – C – A )

A = B

1 = 1 – 0

1 ( 1 – 0 ) = ( 1 – 0 )2

1 ( 1 ) – 1 ( 0 ) = 12 – 2 ( 0 ) ( 1 ) + 02

1 ( 1 ) – 1 ( 0 ) – 02 = 12 – 2 ( 0 ) ( 1 )

0 ( 1 ) + 1 ( 1 ) – 1 ( 0 ) – 02 = 12 – 1 ( 1 ) – 0 ( 1 )

0 ( 1 ) – 1 ( 0 ) – 02 = 12 – 1 ( 1 ) – 0 ( 1 )

0 ( 1 – 1 – 0 ) = 1 ( 1 – 1 – 0 )

0 = 1

1 = 2 – 1

1 ( 2 – 1 ) = ( 2 – 1 )2

1 ( 2 ) – 1 ( 1 ) = 22 – 2 ( 1 ) ( 2 ) + 12

1 ( 2 ) – 1 ( 1 ) – 12 = 22 – 2 ( 1 ) ( 2 )

1 ( 2 ) + 1 ( 2 ) – 1 ( 1 ) – 12 = 22 – 1 ( 2 ) – 1 ( 2 )

1 ( 2 ) – 1 ( 1 ) – 12 = 22 – 1 ( 2 ) – 1 ( 2 )

1 ( 2 – 1 – 1 ) = 2 ( 2 – 1 – 1 )

1 = 2

1 = 3 – 2

1 ( 3 – 2 ) = ( 3 – 2 )2

1 ( 3 ) – 1 ( 2 ) = 32 – 2 ( 2 ) ( 3 ) + 22

1 ( 3 ) – 1 ( 2 ) – 22 = 32 – 2 ( 2 ) ( 3 )

2 ( 3 ) + 1 ( 3 ) – 1 ( 2 ) – 22 = 32 – 1 ( 3 ) – 2 ( 3 )

2 ( 3 ) – 1 ( 2 ) – 22 = 32 – 1 ( 3 ) – 2 ( 3 )

2 ( 3 – 1 – 2 ) = 3 ( 3 – 1 – 2 )

2 = 3

1 = 4 – 3

1 ( 4 – 3 ) = ( 4 – 3 )3

1 ( 4 ) – 1 ( 3 ) = 43 – 3 ( 3 ) ( 4 ) + 33

1 ( 4 ) – 1 ( 3 ) – 33 = 43 – 3 ( 3 ) ( 4 )

3 ( 4 ) + 1 ( 4 ) – 1 ( 3 ) – 33 = 43 – 1 ( 4 ) – 3 ( 4 )

3 ( 4 ) – 1 ( 3 ) – 33 = 43 – 1 ( 4 ) – 3 ( 4 )

3 ( 4 – 1 – 3 ) = 4 ( 4 – 1 – 3 )

3 = 4

1 = 5 – 4

1 ( 5 – 4 ) = ( 5 – 4 )2

1 ( 5 ) – 1 ( 4 ) = 52 – 2 ( 4 ) ( 5 ) + 42

1 ( 5 ) – 1 ( 4 ) – 42 = 52 – 2 ( 4 ) ( 5 )

4 ( 5 ) + 1 ( 5 ) – 1 ( 4 ) – 42 = 52 – 1 ( 5 ) – 4 ( 5 )

4 ( 5 ) – 1 ( 4 ) – 42 = 52 – 1 ( 5 ) – 4 ( 5 )

4 ( 5 – 1 – 4 ) = 5 ( 5 – 1 – 4 )

4 = 5

1 = 6 – 5

1 ( 6 – 5 ) = ( 6 – 5 )2

1 ( 6 ) – 1 ( 5 ) = 62 – 2 ( 5 ) ( 6 ) + 52

1 ( 6 ) – 1 ( 5 ) – 52 = 62 – 2 ( 5 ) ( 6 )

5 ( 6 ) + 1 ( 6 ) – 1 ( 5 ) – 52 = 62 – 1 ( 6 ) – 5 ( 6 )

5 ( 6 ) – 1 ( 5 ) – 52 = 62 – 1 ( 6 ) – 5 ( 6 )

5 ( 6 – 1 – 5 ) = 6 ( 6 – 1 – 5 )

5 = 6

1 = 7 – 6

1 ( 7 – 6 ) = ( 7 – 6 )2

1 ( 7 ) – 1 ( 6 ) = 72 – 2 ( 6 ) ( 7 ) + 62

1 ( 7 ) – 1 ( 6 ) – 62 = 72 – 2 ( 6 ) ( 7 )

6 ( 7 ) + 1 ( 7 ) – 1 ( 6 ) – 62 = 72 – 1 ( 7 ) – 6 ( 7 )

6 ( 7 ) – 1 ( 6 ) – 62 = 72 – 1 ( 7 ) – 6 ( 7 )

6 ( 7 – 1 – 6 ) = 7 ( 7 – 1 – 6 )

6 = 7

1 = 8 – 7

1 ( 8 – 7 ) = ( 8 – 7 )2

1 ( 8 ) – 1 ( 7 ) = 82 – 2 ( 7 ) ( 8 ) + 72

1 ( 8 ) – 1 ( 7 ) – 72 = 82 – 2 ( 7 ) ( 8 )

7 ( 8 ) + 1 ( 8 ) – 1 ( 7 ) – 72 = 82 – 1 ( 8 ) – 7 ( 8 )

7 ( 8 ) – 1 ( 7 ) – 72 = 82 – 1 ( 8 ) – 7 ( 8 )

7 ( 8 – 1 – 7 ) = 8 ( 8 – 1 – 7 )

7 = 8

1 = 9 – 8

1 ( 9 – 8 ) = ( 9 – 8 )2

1 ( 9 ) – 1 ( 8 ) = 92 – 2 ( 8 ) ( 9 ) + 82

1 ( 9 ) – 1 ( 8 ) – 82 = 92 – 2 ( 8 ) ( 9 )

8 ( 9 ) + 1 ( 9 ) – 1 ( 8 ) – 82 = 92 – 1 ( 9 ) – 8 ( 9 )

8 ( 9 ) – 1 ( 8 ) – 82 = 92 – 1 ( 9 ) – 8 ( 9 )

8 ( 9 – 1 – 8 ) = 9 ( 9 – 1 – 8 )

8 = 9

1 = 10 – 9

1 ( 10 – 9 ) = ( 10 – 9 )2

1 ( 10 ) – 1 ( 9 ) = 102 – 2 ( 9 ) ( 10 ) + 92

1 ( 10 ) – 1 ( 9 ) – 92 = 102 – 2 ( 9 ) ( 10 )

9 ( 10 ) + 1 ( 10 ) – 1 ( 9 ) – 92 = 102 – 1 ( 10 ) – 9 ( 10 )

9 ( 10 ) – 1 ( 9 ) – 92 = 102 – 1 ( 10 ) – 9 ( 10 )

9 ( 10 – 1 – 9 ) = 10 ( 10 – 1 – 9 )

9 = 10

Etc.

Using this logic, we can henceforth assume that all whole, rational numbers are equal to each other. Thusly, I have proven that math is completely useless to everyone.

>:3

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